Chemistry · BGCSE / Formulae, equations and moles
StructuredPast exam questionForm 5 · BGCSE
Hazel reacted 25.0 cm³ of a 2.0 mol/dm³ hydrochloric acid solution with 2.0 g of an unknown carbonate of formula XCO₃. She titrated the resulting mixture with aqueous sodium hydroxide. The unreacted hydrochloric acid needed 10 cm³ of 1.0 mol/dm³ sodium hydroxide to neutralise it. XCO₃ + 2HCl → XCl₂ + CO₂ + H₂O.
- aWrite the equation for the reaction between hydrochloric acid and sodium hydroxide. [1]
- bCalculate the number of moles in 10 cm³ of 1.0 mol/dm³ sodium hydroxide. [1]
- cState the number of moles of hydrochloric acid that reacted with the sodium hydroxide. [1]
- dCalculate the number of moles in 25 cm³ of 2.0 mol/dm³ hydrochloric acid. [2]
- eCalculate the number of moles of hydrochloric acid that reacted with 2.0 g of XCO₃. [2]
- fCalculate the number of moles of XCO₃ in 2.0 g. [1]
- gCalculate the mass of 1 mole of XCO₃. [1]
- hCalculate the relative atomic mass of element X. [2]
- iIdentify element X from the Periodic Table. [1]
You'll mark your own answer against the marking guide when you hand it in.
Source: BEC BGCSE Chemistry 2004, Paper 3, Question 4
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